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x² Quadratic Formula Calculator

Solve any quadratic equation ax² + bx + c = 0 using the quadratic formula. Computes the discriminant, both roots (real or complex), and the vertex of the parabola — with full step-by-step working.

x = (−b ± √(b² − 4ac)) / (2a)

The Quadratic Formula Explained

Formula: x = (−b ± √(b² − 4ac)) / (2a)
Discriminant: Δ = b² − 4ac
Vertex: x = −b/(2a)    y = c − b²/(4a)

How to Solve a Quadratic Equation

  1. 1
    Write in Standard Form
    Rearrange so the equation is ax² + bx + c = 0 with a ≠ 0.
  2. 2
    Identify Coefficients
    Pick out the values of a (x² coeff.), b (x coeff.), and c (constant).
  3. 3
    Compute the Discriminant
    Calculate Δ = b² − 4ac. Its sign determines root type.
  4. 4
    Apply the Formula
    Substitute into x = (−b ± √Δ) / 2a. Use + for x₁, − for x₂.
  5. 5
    Find the Vertex
    x-vertex = −b/(2a); y-vertex = c − b²/(4a). Vertex is the parabola's turning point.

Example — x² − 5x + 6 = 0

a = 1, b = −5, c = 6
Δ = (−5)² − 4(1)(6) = 25 − 24 = 1
Δ > 0 → Two distinct real roots
x₁ = (5 + √1) / 2 = 6/2 = 3
x₂ = (5 − √1) / 2 = 4/2 = 2
Vertex: x = 5/2 = 2.5,   y = 6 − 25/4 = −0.25
Check: (x−3)(x−2) = x² − 5x + 6 ✓

Frequently Asked Questions

The quadratic formula x = (−b ± √(b²−4ac)) / (2a) gives the solutions to any quadratic equation ax² + bx + c = 0. It was derived by completing the square and works for all quadratics.

The discriminant Δ = b² − 4ac tells you the nature of the roots before you solve. Δ > 0: two distinct real roots. Δ = 0: one repeated real root. Δ < 0: two complex conjugate roots.

Complex roots (a ± bi where i = √−1) occur when the parabola does not cross the x-axis. They always come in conjugate pairs. While not real numbers, complex roots are used extensively in engineering and physics.

The vertex is the highest or lowest point of the parabola y = ax² + bx + c. Its x-coordinate is −b/(2a) and y-coordinate is found by substituting back. If a > 0 the vertex is a minimum; if a < 0 it is a maximum.

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